Question

Factorise (3a-5a)^3+(5b-7c)^3+(7c-3a)^3

Answer 1

Answer:

Step-by-step explanation:

As there is an Identity in Maths:-

Let,

=> a = 3a-5b

=> b = 4c-3a

=> c = 5b-4c

+

____________________

=> a+b+c = 0

If,

 =  >  {a}^{3} +  {b}^{3} +  {c}^{ 3} = 3abc  

=  >  ({3a - 5b})^{3} +( {4c - 3a})^{3} + (5b - 4c)^{2}  = 3(3a - 5b)(4c - 3a)(5b - 4c)

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