Question

Factorise (3a-5b)^3+(4c-3a)^3+(5b-4c)^3

Answer 1

As there is an Identity in Maths:-

Let,
=> a = 3a-5b
=> b = 4c-3a
=> c = 5b-4c
+
____________________

=> a+b+c = 0

If,

$= > {a}^{3} + {b}^{3} + {c}^{ 3} = 3abc$

$= > ({3a - 5b})^{3} +( {4c - 3a})^{3} + (5b - 4c)^{2} = 3(3a - 5b)(4c - 3a)(5b - 4c)$



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Answer 2

Step-by-step explanation:

3(3a-5b)(4c-3a)(5b-4c)

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