Factorise
(3a+5b)cube - (3a-5b)cube
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Answer:
(3a+5b)^3 - (3a- 5b)^3
using (a^3 -b^3)=(a -b) (a^2+ab+b^2)
=(3a-5b-3a-5b)[(3a-5b)^2+(3a+5b)^2 +(3a-5b)(3a+5b)]
=(-10b)[9a^2-2×3a×5b+25b^2+9a^2+2×3a×5b+25b^2+9a^2-25b^2]
=(-10b)[9a^2+25b^2+9a^2+9a^2]
=(-10b)(27a^2+25b^2)
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