Question

Factorise: 3a + 9b - 4(a +3b)^2​

Answer 1

Answer:  

Factors of 2a+6b-3(a+3b)²=

(a+3b)(2-3a-9b)

Step-by-step explanation:

Factorising 2a+6b-3(a+3b)²

= 2(a+3b)-3(a+3b)(a+3b)

= (a+3b)[2-3(a+3b)]

= (a+3b)(2-3a-9b)

Therefore,

2a+6b-3(a+3b)²

= (a+3b)(2-3a-9b)

Answer 2

Answer:

-4a²-24ab-36²+3a+9b is the answer

Step-by-step explanation:

$3a+9b-4(a+3b)^2$

$(a+b)^2=a^2+b^2+2ab$

$3a+9b-4(a^2+9b^2+2 * a * 3b )$

$3a+9b-4(a²+9b²+6ab)$

$3a+9b-4a^2-36b^2-24ab$

$-4a²-24ab-36²+3a+9b$

Hope It Helps You