Factorise (3a - Sb) + (4c-3a)3 + (56-4c)
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Answer:
-18a+24c
Step-by-step explanation:
(3a-5b)+(12c-9a)+(5b-4c)
Substitute (3a-5b) with a (12c-9a) with b and (5b-4c) with c
(a+b+c)² = a² + b² + c² + 2(ab+bc+ca)
= (3a-5b)+(12c-9a)+(5b-4c)+2[(3a-5b)+(12c-9a)+(5b-4c)]
=3a-5b+12c-9a+5b-4c +6a-10b+24c-18a+10b-8c
{-5band+5b will get cancelled and - 10band+10b will get cancelled}
= -18a+24c
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