Question

factorise 3a square+24a+36​

Answer 1

Step-by-step explanation:

3a^2+24a+36=0

dividing it by 3

a^2+8a+12=0

a^2+6a+2a+12=0

a(a+6)+2(a+6)=0

(a+6)(a+2)=0

a=(-6)or a=(-2)

Answer 2

Step-by-step explanation:

Method 1 :-

By Middle term splitt -

3a² + 24a + 36 = 0

= 3a² + 6a + 18a + 36

= 3a(a + 2) + 18(a + 2)

= (3a + 18)(a + 2)

Zeroes are -

3a + 18 = 0 and a + 2 = 0

3a = - 18 and a = - 2

a = -18/3 and a = - 2

• a = - 6 and a = - 2

Method 2 :-

Using Quadratic formula -

Quadratic formula -

• x = - b ± √b² - 4ac/2a

3a² + 24a + 36

here,

a = 3

b = 24

c = 36

Now,

a = -(24) ± √(24)² - 4×3×36/2(3)

= -24 ± √576 - 432/6

= -24 ± √144/6

= -24 ± 12/6

Hence,

The zeroes are -

a = -24 + 12/6

= -12/6

• = -2

And

a = -24 - 12/6

= -36/6

• = -6