Question

factorise 3b(2-c)-4a(2-c)​

Answer 1

Question :

Factorise 3b(2-c)-4a(2-c)

Solution :

3b(2-c)-4a(2-c)

Taking (2-c) common ,

$\tt \implies$ (2-c)(3b-4a)

Hence factorised.

3b(2-c)-4a(2-c) = (2-c)(3b-4a)

Answer 2

Answer:

3b(2-c)-4a(2-c)

=6b - 3bc - 8a + 4ac

=6b - 8a -3bc + 4ac

= 2(3b-4a) -c(3b-4a)

=(2-c) (3b-4a)