Math, asked by ishaannsr0307, 2 months ago

factorise 3t³-t²-3t+1​

Answers

Answered by Shorya9939
1

Answer:

( t2 - 1 ) ( 3t - 1 )

Step-by-step explanation:

hope this will Help you

Answered by OshivaniM
1

Answer:

(t-1)(3t-1)(t+1)

or

= (t²-1)(3t-1)

Step-by-step explanation:

3t³ -(3t²-2t²) -(2t+t) +1

= 3t³ -3t²+2t² -2t-t +1

= 3t²(t-1) + 2t(t-1) -1(t-1)

= (t-1)(3t²+2t-1)

= (t-1)(3t²+3t-t-1)

= (t-1)[3t(t+1) -1(t+1)]

=(t-1)(3t-1)(t+1)

or

= (t²-1)(3t-1)

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