Math, asked by boregowdahm, 1 month ago

Factorise 3u^3-4u^2-12u+16

Answers

Answered by ashakirandesai74
0

Answer:

(3u-4) (u+2) (u-2)

Step-by-step explanation:

Add and subtract the second term to the expression and factor by grouping.

Answered by satwiksingh483
1

Answer:

3u^3 - 4u2-12 u + 16

=(3u^3 -4u^2) - (12u- 16)

= u^2 (3u- 4) - 4( 3u-4)

= ( u^2 -4)(3u-4)

= ( u-2 )(u +2)(3u - 4)

Step-by-step explanation:

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