Factorise:3x^2-2root6x+2=0
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3x^2-2√6x+2=0
3x^2-(√6+√6)x+2=0
3x^2-√6x-√6x+2=0
√3x(√3x-√2)-√2(√3x-√2)=0
(√3x-√2) (√3x-√2)=0
if √3x-√2=0
x=√2/√3 Ans
and if √3x-√2=0
x=√2/√3
therefore both values of x is √2/√3..Ans
i hope u understand..
plz mark as brainliest..☺☺☺
3x^2-(√6+√6)x+2=0
3x^2-√6x-√6x+2=0
√3x(√3x-√2)-√2(√3x-√2)=0
(√3x-√2) (√3x-√2)=0
if √3x-√2=0
x=√2/√3 Ans
and if √3x-√2=0
x=√2/√3
therefore both values of x is √2/√3..Ans
i hope u understand..
plz mark as brainliest..☺☺☺
Answered by
2
Answer:
x= √2 / √3
Step-by-step explanation:
3x²-2√6 x + 2 = 0
3x²-√6 x - √6x + 2 = 0
3x{x-(√2/√3)} - √6{x-(√2/√3)} = 0
(3x-√6){x-(√2/√3)} = 0
x = √6/3 =√2/√3
x- √2/√3=0 so x = √2/√3
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