Question

factorise 3x^2+6x-24 please solve the question​

Answer 1

$3 {x}^{2} + 6x - 24$

$3 {x}^{2} + (12 - 6)x - 24$

$3 {x}^{2} + 12x - 6x - 24$

$3x(x + 4) - 6(x + 4)$

$(x + 4)(3x - 6)$

Answer 2

We have , 3x²+6x-24

In order to factories we use : Splitting the middle term method !!

$\implies\tt{24 \times 3 = 72 \: and \: factors \: are \: 12 \: and \: 6}$

$\implies \tt{ 3{x}^{2} + 12x - 6x - 24} \\ \implies \tt{3x(x + 4) - 6(x + 4)} \\ \implies \tt{(x + 4)(3x - 6)}$

Additional Information :

• In order to factorise x² + bx + c we have to find numbers p and q which are factors of c and even p + q = b or p - q = b
• After finding p and q we just split the middle term as px and qx and find the required the terms needed !!