factorise (3x-2y)^2+3(3x-2y-10)
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Answer:
(3x-2y+5) (3x-2y-2)
Step-by-step explanation:
(3x-2y)^2 + 3(3x-2y)-10
Assume that 3x-2y=a
therefore,
(3x-2y)^2 +3(3x-2y)-10
=a^2+3a-10
=a^2+5a-2a-10
=a(a+5)-2(a+5)
=(a+5) (a-2)
=(3x-2y+5) (3x-2y-2)
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