Factorise 3x^3-4x*2-12x+16
Answers
Answer:
Factorize 3x^3 - 4x^2 - 12x + 16
Step 1 :Equation at the end of step 1 : (((3 • (x3)) - 22x2) - 12x) - 16 = 0
Step 2 :Equation at the end of step 2 : ((3x3 - 22x2) - 12x) - 16 = 0 Step 3 :Checking for a perfect cube :
3.1 3x3-4x2-12x-16 is not a perfect cube
Trying to factor by pulling out :
3.2 Factoring: 3x3-4x2-12x-16
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 3x3-16
Group 2: -4x2-12x
Pull out from each group separately :
Group 1: (3x3-16) • (1)
Group 1: 3x3-16
Group 2: -4x2-12x
Pull out from each group separately :
Group 1: (3x3-16) • (1)
Group 2: (x+3) • (-4x)
Step 2 :Equation at the end of step 2 : ((3x3 - 22x2) - 12x) - 16 = 0 Step 3 :Checking for a perfect cube :
3.1 3x3-4x2-12x-16 is not a perfect cube
Trying to factor by pulling out :
3.2 Factoring: 3x3-4x2-12x-16
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 3x3-16
Group 2: -4x2-12x
Pull out from each group separately :
Group 1: (3x3-16) • (1)
Group 2: (x+3) • (-4x)
Step-by-step explanation: