factorise 3x^3+7x and find out if 7+3x is a factor of 3x^3+7x
Answers
Answer
Answer
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Answer∣∣
Answer∣∣∣
Answer∣∣∣∣
Answer∣∣∣∣∣
Answer∣∣∣∣∣∣
Answer∣∣∣∣∣∣∣
Answer∣∣∣∣∣∣∣∣
Answer∣∣∣∣∣∣∣∣
Answer∣∣∣∣∣∣∣∣
Answer∣∣∣∣∣∣∣∣ x−2
Answer∣∣∣∣∣∣∣∣ x−2x−4
Answer∣∣∣∣∣∣∣∣ x−2x−4x−8
Answer∣∣∣∣∣∣∣∣ x−2x−4x−8
Answer∣∣∣∣∣∣∣∣ x−2x−4x−8
Answer∣∣∣∣∣∣∣∣ x−2x−4x−8 2x−3
Answer∣∣∣∣∣∣∣∣ x−2x−4x−8 2x−32x−9
Answer∣∣∣∣∣∣∣∣ x−2x−4x−8 2x−32x−92x−27
Answer∣∣∣∣∣∣∣∣ x−2x−4x−8 2x−32x−92x−27
Answer∣∣∣∣∣∣∣∣ x−2x−4x−8 2x−32x−92x−27
Answer∣∣∣∣∣∣∣∣ x−2x−4x−8 2x−32x−92x−27 3x−4
Answer∣∣∣∣∣∣∣∣ x−2x−4x−8 2x−32x−92x−27 3x−43x−16
Answer∣∣∣∣∣∣∣∣ x−2x−4x−8 2x−32x−92x−27 3x−43x−163x−64
2
24
24x−8
24x−8
24x−8
24x−8 0
24x−8 06
24x−8 06−x−3
24x−8 06−x−3
24x−8 06−x−3
24x−8 06−x−3 0
24x−8 06−x−3 024
24x−8 06−x−3 024−3x−16
24x−8 06−x−3 024−3x−162
24x−8 06−x−3 024−3x−162
24x−8 06−x−3 024−3x−162 →C
24x−8 06−x−3 024−3x−162 →C 2−3C 1 C →C 3 −6C 1
EExpandingalong
=2[6(−3x−16)−24(−x−3)]
=2[6(−3x−16)−24(−x−3)]=2[−18x−96+24x+72]
=2[6(−3x−16)−24(−x−3)]=2[−18x−96+24x+72]=2[6x−24]
=2[6(−3x−16)−24(−x−3)]=2[−18x−96+24x+72]=2[6x−24]=12(x−4)
=2[6(−3x−16)−24(−x−3)]=2[−18x−96+24x+72]=2[6x−24]=12(x−4)