Question

factorise (3x+4)³-8 factorise​

Answer 1

Answer:

Since both terms are perfect cubes, factor using the difference of cubes formula,

a

3

−

b

3

=

(

a

−

b

)

(

a

2

+

a

b

+

b

2

)

where

a

=

3

x

+

4

and

b

=

2

.

(

3

x

+

2

)

(

9

x

2

+

30

x

+

28

)

hope it helps u....

Answer 2

Answer:

$(3x + 2)(9 {x}^{2} + 32x + 28)$

Step-by-step explanation:

${(3x + 4)}^{3} - 8 \\ = (3x + 4)^{3} - {(2)}^{3} \\ \\ by \: using \: identity \: \\ {x}^{3} - {y}^{3} =(x - y)( {x}^{2} + xy + {y}^{2} ) \\ \\ = (3x + 4 - 2)((3 x + 4)^{2} + (3x + 4) 2 + (2)^{2}) \\ = (3x + 2)(9 {x}^{2} + 24x + 16 + 6x + 8 + 4) \\ = (3x + 2)(9 {x}^{2} + 32x + 28)$