factorise 3x^5+1536x^2y^3
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Answered by
28
Hi,
3x^5 + 1536x²y³
= 3x²( x³ + 512y³ )
= 3x²[ x³ + ( 8y )³ ]
= 3x²{ ( x + 8y) [ x² - x × (8y ) + ( 8y )² ] }
= 3x² ( x + 8y ) ( x² - 8xy + 64y² )
I hope this helps you.
:)
3x^5 + 1536x²y³
= 3x²( x³ + 512y³ )
= 3x²[ x³ + ( 8y )³ ]
= 3x²{ ( x + 8y) [ x² - x × (8y ) + ( 8y )² ] }
= 3x² ( x + 8y ) ( x² - 8xy + 64y² )
I hope this helps you.
:)
Answered by
12
Answer:
3x^5 + 1536x²y³
= 3x²( x³ + 512y³ )
= 3x²[ x³ + ( 8y )³ ]
= 3x²{ ( x + 8y) [ x² - x × (8y ) + ( 8y )² ] }
= 3x² ( x + 8y ) ( x² - 8xy + 64y² )
Step-by-step explanation:
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