Math, asked by mdamit, 9 months ago

Factorise: 3x^5y^3+24x^2​

Answers

Answered by chandan454380
2

Answer:

The answer is 3x^2(xy+2)(x^2y^2-2xy+4)

Step-by-step explanation:

Given expression

  3x^5y^3+24x^2

=3x^2(x^3y^3)+3x^2(8)

=3x^2(x^3y^3+8), factor out common

=3x^2[(xy)^3+2^3], write the second expression in a^3+b^3 form

=3x^2(xy+2)[(xy)^2-(xy)(2)+2^2], using a^3+b^3=(a+b)(a^2-ab+b^2)

=3x^2(xy+2)(x^2y^2-2xy+4)

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