Factorise : (3x – 5y)³ + (5y-2z)³+ (2z – 3x)³
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Answer: Let a = (3x-5y)
b = (5y-2z)
c = (2z-3x)
Now, a+b+c = (3x-5y)+(5y-2z)+(2z-3x)
= 3x-5y+5y-2z+2z-3x
= 0
When a+b+c = 0
Then a^3+b^3+c^3 = 3abc
(3x-5y)³ + (5y-2z)³+ (2z-3x)³
= 3(3x-5y)(5y-2z)(2z-3x) is the correct answer.
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