Question

Factorise 3x2 + 11x + 6​

Answer 1

Answer:

$x = \frac{ - 2}{3} \: and \: - 3$

Step-by-step explanation:

3x²+9x+2x+6=0

3x(x+3)+2(x+3)=0

(3x+2)(x+3)=0

x= -2/3 , -3

Answer 2

Answer:

$\boxed{\sf (x + 3)(3x + 2)}$

Step-by-step explanation:

$\sf Factor \: the \: following: \\ \sf \implies 3 {x}^{2} + 11x + 6 \\ \\ \sf The \: coefficient \: of \: {x}^{2} \: is \: 3 \: and \: the \: constant \\ \sf term \: is \: 6. \: The \: product \: of \: 3 \: and \: 6 \: is \: 18. \: The \\ \sf factors \: of \: 18 \: which \: sum \: to \: 11 \: are \: 2 \: and \: 9. \\ \sf So, \\ \\ \sf \implies 3 {x}^{2} + (9 + 2)x + 6 \\ \\ \sf \implies 3 {x}^{2} + 9x + 2x + 6 \\ \\ \sf \implies 3 {x}^{2} + 9x + 2x + 6 \\ \\ \sf \implies 3 x(x + 3) + 2(x + 3) \\ \\ \sf \implies (x + 3)(3x + 2)$