factorise 3x²+11x+6
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Using Splitting the middle term...
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Hello mate..
Here Is Your Answer:
If we can find two numbers p and q such that p + q = 11 and pq = 3 × 6 = 18, then we get the factors.
So, let us see the pairs of factors of 18. (1,18) , (2,9) , (3,6) of these pairs, 2 and 9 will satisfy p + q = 11.
So, 3x² + 11x + 6 = 3x² + 2x + 9x + 6
=> x(3x + 2) + 3(3x + 2)
=> (3x + 2) (x+3)
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HOPE THIS HELPS YOU..
Anonymous:
Perfect !
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