Question

Factorise - 3x2-20x-63

Answer 1

hey mate!!

here's ur answer:-)
__________

$3x {}^{2} - 20x - 63 \\ 3 x{}^{2} - 7x + 27x - 63 \\ 3x(x + 9) - 7(x + 9) \\ (x + 9)(3x - 7)$

________

hope it helps:-)

#thankyou...☺☺

Answer 2

For a polynomial of the form ax2+bx+cax2+bx+c, rewrite the middle term as a sum of two terms whose product is a⋅c=3⋅−63=−189a⋅c=3⋅-63=-189and whose sum is b=20b=202020 out of 20x20x.3x2+20(x)−633x2+20(x)-63Rewrite 2020 as −7-7 plus 27273x2+(−7+27)x−633x2+(-7+27)x-63Apply the distributive property.3x2+(−7x+27x)−633x2+(-7x+27x)-63Remove parentheses.3x2−7x+27x−633x2-7x+27x-63Factor out the greatest common factor from each group.Group the first two terms and the last two terms.(3x2−7x)+(27x−63)(3x2-7x)+(27x-63)Factor out the greatest common factor (GCF) from each group.x(3x−7)+9(3x−7)x(3x-7)+9(3x-7)Factor the polynomial by factoring out the greatest common factor, 3x−73x-7.(3x−7)(x+9)(3x-7)(x+9)x(3x−7)+9(3x−7)x(3x-7)+9(3x-7)Factor the polynomial by factoring out the greatest common factor, 3x−73x-7.(3x−7)(x+9)