Question

Factorise 3x²+27y²+2²_18xy+6root3yz_2root3zx​

Answer 1

Answer:

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Step-by-step explanation:

sorry it's confusing

Answer 2

Step-by-step explanation:

Givenexpression is 3x²+27y²+z²_18xy+6√3yz_2√3zx

=>(√3x)²+(-3√3y)²+z²+2(√3x)(-3√3y)+2(-3√3y)(-z) +2(-z)(√3x)

=>This is in the form of a²+b²+c²+2ab+2bc+2ca

Here a=√3x ; b=-3√3y; c=-z

we know that

a²+b²+c²+2ab+2bc+2ca=(a+b+c)²=(a+b+c)(a+b+c)

=>(√3x)²+(-3√3y)²+z²+2(√3x)(-3√3y)+2(-3√3y)(-z) +2(-z)(√3x)=[(√3x+(-3√3y+(-z)]²

=>(√3 x-3√3 y-z)(√3 x-3√3 y-z)