Question

factorise √3x2 +4x+√3​

Answer 1

Step-by-step explanation:

Given -

Given -3x2+4x+3=0

Given -3x2+4x+3=0Take the constant term to right

Given -3x2+4x+3=0Take the constant term to right3x2+4x=−3

Given -3x2+4x+3=0Take the constant term to right3x2+4x=−3Divide each term on both sides by the coefficient of x2

Given -3x2+4x+3=0Take the constant term to right3x2+4x=−3Divide each term on both sides by the coefficient of x23x23+4x3=−33

Given -3x2+4x+3=0Take the constant term to right3x2+4x=−3Divide each term on both sides by the coefficient of x23x23+4x3=−33x2+43x=−1

Given -3x2+4x+3=0Take the constant term to right3x2+4x=−3Divide each term on both sides by the coefficient of x23x23+4x3=−33x2+43x=−1Divide the coefficient x, square it and add it to both sides

Given -3x2+4x+3=0Take the constant term to right3x2+4x=−3Divide each term on both sides by the coefficient of x23x23+4x3=−33x2+43x=−1Divide the coefficient x, square it and add it to both sidesx2+23x+49=−1+49=−9+49=−59

Given -3x2+4x+3=0Take the constant term to right3x2+4x=−3Divide each term on both sides by the coefficient of x23x23+4x3=−33x2+43x=−1Divide the coefficient x, square it and add it to both sidesx2+23x+49=−1+49=−9+49=−59(x+23)2=−59

Given -3x2+4x+3=0Take the constant term to right3x2+4x=−3Divide each term on both sides by the coefficient of x23x23+4x3=−33x2+43x=−1Divide the coefficient x, square it and add it to both sidesx2+23x+49=−1+49=−9+49=−59(x+23)2=−59Take square root on both sides

Given -3x2+4x+3=0Take the constant term to right3x2+4x=−3Divide each term on both sides by the coefficient of x23x23+4x3=−33x2+43x=−1Divide the coefficient x, square it and add it to both sidesx2+23x+49=−1+49=−9+49=−59(x+23)2=−59Take square root on both sides(x+23)=√−59=√−53

Given -3x2+4x+3=0Take the constant term to right3x2+4x=−3Divide each term on both sides by the coefficient of x23x23+4x3=−33x2+43x=−1Divide the coefficient x, square it and add it to both sidesx2+23x+49=−1+49=−9+49=−59(x+23)2=−59Take square root on both sides(x+23)=√−59=√−53x=±i√−53−23