factorise:√3x²+7x-6√3
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6√3x² + 7x - √3 = 0 => 6√3x² + ( 9 - 2)x - √3 = 0 => 6√3x² + 9x - 2x - √3 = 0 => 3√ 3x(2x + √3) - 1(2x + √3) = 0 => (3√3x - 1) (2x + ..
Answer :Given,6√3x² + 7x - √3 = 0➠ 6√3x² + 9x - 2x - √3 = 0➠ 3√3x (2x + √
Explanation:
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