factorise 3x² + 8√2x - 6
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Answered by
3
Hi friend!!
Here is your answer.
3x² + 8√2x - 6
=3x²+9√2x-√2x-6
=3x(x+3√2)-√2(x+3√2)
=(3x-√2)(x+3√2)
so, 3x-√2 and x+3√2 are the required factors.
I hope this will help u ;)
Here is your answer.
3x² + 8√2x - 6
=3x²+9√2x-√2x-6
=3x(x+3√2)-√2(x+3√2)
=(3x-√2)(x+3√2)
so, 3x-√2 and x+3√2 are the required factors.
I hope this will help u ;)
Answered by
0
HELLO........FRIEND!!
THE ANSWER IS HERE,
:-)Hope it helps u.
THE ANSWER IS HERE,
:-)Hope it helps u.
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