Question

Factorise: 3x² – 8x – 3 using middle term splitting method​

Answer 1

Step-by-step explanation:

$3 {x}^{2} - 8x - 3$

$sum = - 8 \: and \: product \: - 9$

$3 {x}^{2} - 9x + x - 3$

$3x(x - 3) + 1(x - 3)$

$(x - 3)(3x + 1)$

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Answer 2

Answer:-

(x-3)(3x+1)

Step By Step Explanation:-

$3 {x}^{2} - 8x - 3 \\ = 3 {x}^{2} - 9x + x - 3 \\ = (x - 3)(3x + 1)$

Steps to be followed:-

1. Firstly,we can clearly see that there is no common nor a²-b² is applying and nor (a+b)²,(a-b)² is applying.
2. Now,there is only last method to factorise that is splitting.
3. So,we have to multiply the constants of first and last numbers that are 3 and 3.
4. Now,we have to do Prime Factorisation of the result of multiplication that is 9 so that we can find that which factors of it when subtracted gives the number equal to middle number that is 8.So,the factors that gives 8 when subtracted are 9 and 1.
5. Now,we have to split them.So,the equation that made is 3x²-9x+x-3.
6. Now,there is a common number in both variables that is 3x in first one.
7. So,(x-3) is common.Now,the whole answer is (x-3)(3x+1).