Question

factorise 3x³+x²-20x+12​

Answer 1

Answer:

Factor Therome:

Let p(x) be a polynomial of

degree one or more than 1

and is a real number . Then

1)x-q , will be a factor of p(x)

if p(a)=0 conversely

2)If x-a is a factor of p(x),

then p(a)=0

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Here,

F(x)=3x³+x²-20x+12,

g(x)=3x-2,

g(x)=0

=>3x-2=0

=>x=2/3

Zero of g(x)=2/3,

Now,

F(2/3)=3(2/3)³+(2/3)²-20(2/3)+12

= 3(8/27)+4/9-40/3+12

= 8/9+4/9-40/3+12

=12/9-40/3+12

=4/3-40/3+12

= -36/3+12

= -12+12

= 0

By factor therome, g(x) is a

factor of f(x)

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