Question

factorise 3x5-48x3​

Answer 1

Answer:

$\implies \sf 3x^3 (x+4)(x-4)$

Step-by-step explanation:

To Factorize:-

3x⁵ - 48x³

Solution:

$\sf \implies 3x^3.x^2-3x^3.16=0$

$\sf \implies 3x^3 (x^2-16)=0$

$\sf \implies 3x^3 (x^2-4^2)=0$ [(a²-b²)=(a+b)(a-b)]

$\sf \implies 3x^3 (x+4)(x-4)=0$

>> Final Answer:-

$\implies \sf 3x^3 (x+4)(x-4)$

Points to be noted:

• Factorisation is a method to find factors of the given polynomial.

• They are generally written as product of other factors.,

• To factories a quadratic polynomial splitting the middle term is widely used.

• While identities and simplification can also be used to Factorize.

Answer 2

Given Expression :-

$\sf{3 {x}^{5} - 48 {x}^{3} }$

To Find :-

Its Factorised Form.

How To Solve?

Take out Common terms and use the suitable Identity.

Solution :-

$\sf\dashrightarrow{3 {x}^{3}( {x}^{2} - 16)}$

$\sf\dashrightarrow{3 {x}^{3}\{ {(x)}^{2} - {(4)}^{2}\} }$

$\dashrightarrow\boxed{\bf\red{3 {x}^{3}(x + 4)(x - 4) }}$

So, This is the required answer.