Question

factorise 3xcube-4xsquare-12xplus 16

Answer 1

Here's your answer !!

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$= > {3x}^{3} - 4 {x}^{2} - 12x + 16$


$= > {x}^{2} (3x - 4) - 4(3x - 4)$


$= > ( {x}^{2} - 4)(3x - 4)$


$= > ( ({x}) ^{2} - ({2})^{2} )(3x - 4)$


$= > (x - 2)(x + 2)(3x - 4)$

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Hope it helps you !! :)

Answer 2

Answer :-

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Factorise of :- 3x³ - 4x² - 12x + 16

Now ,

3x³ - 4x² - 12x + 16

= x² ( 3x - 4 ) - 4 ( 3x - 4 )

= ( 3x - 4 ) ( x² - 4 )

= ( 3x - 4 ) { ( x )² - ( 2 )² }

= ( 3x - 4 ) ( x + 2 ) ( x - 2 ) [ ★ Required answer ]

Note :-

Used identity :- a² - b² = ( a + b ) ( a - b ) [ • Where , a = x , b = 2 ]

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