factorise 3y^2 + 3y - 36
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3y^2 + 3y - 36 = 0
3y^2 + 12y - 9y - 36 = 0
3y [ y + 4 ] - 9 [ y + 4 ] = 0
[ 3y - 9 ] [ y + 4 ] = 0
∴ 3y = 9 ⇒ y = 3
and,
∴ y = -4
So,
y = 3 , -4
3y^2 + 12y - 9y - 36 = 0
3y [ y + 4 ] - 9 [ y + 4 ] = 0
[ 3y - 9 ] [ y + 4 ] = 0
∴ 3y = 9 ⇒ y = 3
and,
∴ y = -4
So,
y = 3 , -4
Answered by
2
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