factorise 3y^3 +y^2-3y-1
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Answer:
(y-1)(y+1)(3y+1)
Step-by-step explanation:
3y^3 +y^2-3y-1 = 3y³ +y²-3y-1 = 3y³ -3y + y²-1 = 3y(y²-1) +(y²-1)
= (y²-1)(3y+1) = (y-1)(y+1)(3y+1)
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