Question

factorise 3y^3 +y^2-3y-1​

Answer 1

Answer:

(y-1)(y+1)(3y+1)

Step-by-step explanation:

3y^3 +y^2-3y-1​ = 3y³ +y²-3y-1​ = 3y³ -3y + y²-1 = 3y(y²-1) +(y²-1)

= (y²-1)(3y+1) =  (y-1)(y+1)(3y+1)