Question

Factorise : 4) 125y³ - 1​

Answer 1

Aиѕωєr —

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ㅤㅤㅤ$\underline{\boxed{\bf{ (5y-1)(25y^2 +1+5y)}}}$

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Wє cαи ωяiтє iт αѕ —

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• $\large\rm{(5y)^3 -(1)^3}$

Cσиcєρт —

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• Factorisation using identity :—

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ㅤㅤ$\underline{\boxed{\bf{a^3 -b^3 = a^2 + ab+b^2}}}$

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Tнєrєfσrє —

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$\large\rm{\implies (5y)^3-(1)^3}$

ㅤㅤㅤ$\large\rm{\implies (5y-1)\left[(5y)^2 +(1)^2 +(5y)\times (1)\right]}$

ㅤㅤㅤㅤㅤ$\large\rm{\implies (5y-1)(25y^2+1+5y)}$

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❍ Hence your answer is :—

ㅤㅤㅤㅤ$\underline{\boxed{\bf\purple{(5y-1)(25y^2+1+5y) }}}$

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✰ Aвσυт fαcтσrizαтiσи —

In mathematics , factorisation is when you break a number down into smaller numbers that , multiplied together gives you the original number . When you split a number into its factors or divisors , that's factorisation.

✰ Fαcтσrizαтiσи мєтнσd —

The factorisation method uses basic factorization formulas to reduce any algebraic or quadratic equation into its simpler form , where the equations are represented as product of factors instead of expanding the brackets . The factors of any equation can be an integer , a variable or an algebraic expression itself .

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Answer 2

Hey !!! ^_^

Here is your answer

⬇️⬇️⬇️⬇️⬇️⬇️⬇️

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎125y³-1

‎ ‎ ‎ ‎ ‎ ‎use the identity

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎a³-b³

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎(a-b)(a²+ab+b²)

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎(5y)³-(1)³

‎ ‎ ‎ ‎ ‎(5y-1)(25y²+5y+1)

Hope this will help you