Question

factorise 4-16pq-(4p^2+16q^2)​

Answer 1

Answer:

(2+2p+4q)(2-2p-4q)

Step-by-step explanation:

4-(16pq+4p^2+16q^2)

4- (2×2p×4q+(2p)^2+(4q)^2)

4-(2p+4q)^2. (a+b)^2=a^2+b^2+2ab

(2)^2-(2p+4q)^2

(2+2p+4q)(2-2p-4q). {a^2-b^2=(a+b)(a-b)