Question

factorise 4ଶ൅25ଶ൅9ଶെ20െ30൅12

Answer 1

Answer:

Step-by-step explanation:

We have

4x  

2

+9y  

2

+25z  

2

−12xy−30yz+20zx

=[(2x)  

2

+(−3y)  

2

+(5z)  

2

+2(2x)(−3y)+2(−3y)(5z)+2(5z)(2x)]

Comparing with the identity V,

(x+y+z)  

2

≡x  

2

+y  

2

+z  

2

+2xy+2yz+2zx, we get

=(2x−3y+5z)  

2

 

=(2x−3y+5z)(2x−3y+5z).

Answer 2

Answer:

$= )4 {x}^{2} + 25 {y}^{2} + 9 {z}^{2} - 20xy - \\ 30yz + 12zx$

$= ) \: (2x) {}^{2} + (5y) {}^{2} + (3z) {}^{2} - \\ 20xy - 30yz + 12x$

$= ) \: ( - 2x + 5y - 3z) {}^{2}$