Question

factorise 4(2a+b)² - (a-b)²please answer fast​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

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Step-by-step explanation:

$4(2a+b)^2 - (a-b)^2\\\\Using\:\:formula\:\: (a+b)^2 = a^2+2ab+b^2 \:\:\:and\:\:(a-b)^2=a^2-2ab+b^2, we\:\:get:-\\\\4[(2a)^2 +(2\times2a\times b)+(b)^2 ] - [(a)^2 - 2 \times a \times b+(b)^2]\\\\4 (4a^2 + 4ab + b^2) - (a^2 - 2ab+b^2)\\\\16a^2+16ab+4b^2-a^2+2ab-b^2\\\\16a^2 - a^2 +16ab +2ab + 4b^2-b^2\\\\15a^2 + 18ab + 3b^2$