Math, asked by belipaul4567, 16 days ago

Factorise

4(2x+3y)^2−9(2x−3y)^2​

Answers

Answered by OmMore02869
1

Answer:

Answer⏬⏬

4(2x-3y)2-8x+12y-3

= 4(2x-3y)²-4(2x-3y) - 3

Let us assume that 2x - 3y = a

Then the given expression is

4(2x-3y)2-8x+12y-3

= 4a²-4a-3

= 4a²-6a + 2a-3

= 2a(2a-3) + 1(2a-3)

= (2a-3)(2a + 1)

= [2(2x-3y) - 3 ][ 2(2x-3y) + 1]

= (4x - 6y - 3)(4x - 6y + 1)

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