Factorise:4(3 + 4)²+(3m + 4n)–5
pls do it fast
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4\left(3+4\right)^2+\left(3m+4n\right)-5
=4\left(3+4\right)^2+3m+4n-5
=7^2\cdot \:4+3m+4n-5
=196+3m+4n-5
=3m+4n+191
HOPE IT HELPS U :D
Answered by
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Answer:
4(3+4)^2+(3m+4n)-5
4(7)^2+(3m+4n)-5
4+×49+(3m+4n)-5
196-5+(3m+4n)
191+3m+4n
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