Question

Factorise: 4√3 X² + 5x -2√3.​

Answer 1

$4 \sqrt3 \: {x}^{2} + 8x - 3x - 2 \sqrt{3} \\ 4x( \sqrt{3} x+ 2) - \sqrt{3} ( \sqrt{3}x + 2) \\ (4 x- \sqrt{3} )( \sqrt{3} x + 2) = 0 \\ x = \sqrt{3} \div 4 \\ x = - 2 \div \sqrt{3}$

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Answer 2

Step-by-step explanation:

$4 \sqrt{3 {}^{} } {x}^{2} + 5x = 2 \sqrt{3}$

$x = - b (+)or( - ) \ \frac{ \sqrt{b {}^{2} - 4ac } }{2a}$

$x = - 5 + or - \frac{ \sqrt{25 - 4( - 24)} }{8 \sqrt{3} }$

$x = - 5 (+ or - ) \frac{ \sqrt{25 + 96} }{8 \sqrt{3} }$

$x = - 5( + or - ) \frac{ \sqrt{121} }{8 \sqrt{3} }$

$x = - 5( + or - ) \frac{11}{8 \times 1.73}$

$x = - 5 + \frac{11}{13.84} \: or \: - 5 - \frac{11}{13.84}$

$x = - 5 + 0.8 \: or \: - 5 - 0.8$

$x = - 4.2 \: or \: - 5.8$