Question

Factorise (4+3x-9) (8-9x+8)

Answer 1

Hi mate the answer is attached

Answer 2

Hey mate here we go

$lets \: write \: eq \\ (4 + 3x - 9)(8 - 9x + 8) \\ (4 \times 8 - 4 \times 9x + 4 \times 8) + \\ (3x \times 8 - 3x \times 9x + 3x \times 8 ) - \\ (9 \times 8 - 9 \times 9x + 9 \times 8) \\ = (32 - 36x + 32) +(24x - 27 {x}^{2} + 24x) \\ - (72 - 81x + 72) \\ = (64 - 36x) + (48x - 27 {x}^{2} ) - \\ (144 -81x) \\ = 64 - 144 - 36x + 48x +81x - 27 {x}^{2} \\ = 80 - 93x - 27 {x}^{2} \\ or= 27 {x}^{2} + 93x - 8$

I hope this will helps you

mark my ans as brainliest