factorise (4/5x-2)^3
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Given: 4x4−5x2+1
=4y2−5y+1, (let x2=y)
=4y2−4y−y+1, (split the middle term)
=(4y2−4y)+(−y+1), (group pair of terms)
=4y(y−1)−1(y−1), (factor each binomials)
=(y−1)(4y−1), (factor out common factor (y−1))
=(x2−1)(4x2−1), (substitute back y=x2)
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