Question

factorise 4(a-1)²-4(a-1)-3​

Answer 1

Answer:

4(a²+1-2a)-4a+4-3

= 4a²+4-8a-4a+4-3

= 4a²-8a+5

=4a²-4a-5a+5

=4a(a-1)-5(a-1)

=(4a-5)(a-1)

hope you like my answer

Answer 2

Step-by-step explanation:

let the a-1 be x

4x^2-4x-3

4x^2-6x+2x-3

2x(2x-3) +1(2x-3)

(2x-3) (2x+1)

x=a-1

(2(a-1)-3) (2(a-1)+1)

(2a-2-3) (2a-2+1)

(2a-5) (2a-1)