Question

Factorise -4(a-2b)+8(a-2b)power2

Answer 1

Answer:

follow my stepsits always correct

step_by_step:

=[{-4(a-2b)+8(a-2b)}² ]

=[{-4a+8b+8a-16b}²]

=[4a-8b]²

=4a-8b²

Answer 2

Since both terms are perfect squares, factor using the difference of squares formula,
a
2
−
b
2
=
(
a
+
b
)
(
a
−
b
)
a
2
-
b
2
=
(
a
+
b
)
(
a
-
b
)
where
a
=
a
+
b
a
=
a
+
b
and
b
=
a
−
b
b
=
a
-
b
.
(
a
+
b
+
a
−
b
)
(
a
+
b
−
(
a
−
b
)
)
(
a
+
b
+
a
-
b
)
(
a
+
b
-
(
a
-
b
)
)