Question

factorise 4 a b + 8 a minus b minus 2
$4ab + 8a - b - 8$

Answer 1

according to the question which you have typed
4ab+8a-b-2
now group
(4ab+8)-(b-2)
taking common 4a in first and 1 in second I.e.
4a(b+2)-1(b+2)
ans is (4a-1)(b+2)
ii)- group(4ab-b)+(8a-8)
so taking 4b common in 1 bracket and 8 in second
4b(a-1)+8(a-1)
ans is (4b+8)(a-1)