Question

factorise 4 in bracket x minus 5 whole square minus 12 in bracket x minus y in bracket X + Y + 9 in bracket X + Y square

Answer 1

Answer:

The factors are (x+5y) and (x+5y)

Step-by-step explanation:

I think your question may be

Factorize:

4(x-y)^2-12(x-y)(x+y)+9(x+y)^2

Formula used:

$(a-b)^2=a^2+b^2-2ab$

Now,

$4(x-y)^2-12(x-y)(x+y)+9(x+y)^2\\\\=4a^2-12ab+9b^2$

where a=x-y and b=x+y

$=(2a)^2-2.(2a)(3b)+(3b)^2\\\\=[2a-3b]^2\\\\=[2(x-y)-3(x+y)]^2\\\\=[2x-2y-3x-3y]^2\\\\=[-x-5y]^2\\\\=[x+5y]^2\\\\=(x+5y)(x+5y)$

Answer 2

Answer:

bro this is the correct answer .all the other answer was wrong.so please mark me as brainliest