Question

Factorise:4(p+q)²-8(p+q)​

Answer 1

Answer:

$4(p + q) ^{2} - 8(p + q) \\ = (p + q)(4(p + q) - 8) \\ = 4\times (p + q)(p + q - 2)$

Answer 2

Answer:

4[p+q]²-8[p+q]

4[p²+q²+2pq]-8p-8q

4p²+4q²+8pq-8p-8q=0

4[p²+q²+2pq-2p-2q]=0

p²+q²-1=0

p²+q²=1

Step-by-step explanation:

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