Question

factorise 4(p+q)(3a-b)+6(p+q)(2b-3a)​

Answer 1

Step-by-step explanation:

4(p + q)(3a - b) + 6(p + q)(2b - 3a)

= 2(p + q) [2(3a - b) + 3(2b - 3a)]

= 2(p + q) [6a - 2b + 6b - 9a]

= 2(p + q) (-3a + 4b)

= -2(p + q) (3a - 4b)