Question

Factorise 4(p+q)(3a-b)+6(p+q)(2b-3a)

Answer 1

4(p+q)(3a-b)+6(p+q)(2b-3a) =  2(p+q)[2(3a-b) + 3(2b-3a)]
                                              =  2(p+q)[6a - 2b + 6b - 9a]
                                              =  2(p+q)[4b - 3a]

Answer 2

To factorise the following the given equation in the question,we have to follow these steps mentioned below:

4(p+q)(3a-b)+6(p+q)(2b-3a)

=2(p+q) {2(3a-b) + 3(2b-3a)}

=2(p+q)(6a - 2b + 6b - 9a)

=2(p+q)(4b - 3a)

So answer of the given factorization in the question is;

2(p+q)(4b - 3a) [answer]