Factorise
4(q-p) (3a-b)+6(p-q) (2b-3a)
Process should be mentioned.
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Answer:
4(p+q)(3a-b)+6(p+q)(2b-3a)
= 2(p+q) [2(3a-b)+3(2b-3a)]
= 2(p+q) [6a-2b+6b-9a]
= 2(p+q)[4b-3a]
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