factorise 4 square + 9 b square + 9 c square + 12 ab+ 4ac + 6 bc
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its easy just u need to analize it
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using ID~(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ac
here,a=√4a=2a,b=√9b=3b,c=√9c=3c
so,
(2a+3b+3c)^2=(2a)^2+(3b)^2+(3c)^2+2×(2a)×(3b)+2×(3b)×(3c)+2×(2a)×(3c)
so,the answer is (2a+3b+3c)^2.............☺️
here,a=√4a=2a,b=√9b=3b,c=√9c=3c
so,
(2a+3b+3c)^2=(2a)^2+(3b)^2+(3c)^2+2×(2a)×(3b)+2×(3b)×(3c)+2×(2a)×(3c)
so,the answer is (2a+3b+3c)^2.............☺️
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