factorise : 4(x^2+1)+13(x^2+1)-12
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correct equation:
4 (x^2 + 1 )^2 + 13 ( x^2 + 1 ) - 12
=4( x^2 + 1)^2 + 16 ( x^2 + 1 ) - 3 ( x^2 + 1 ) - 12
= 4 ( x^2 + 1 ) [ (x^2 + 1 )+ 4 ] - 3 [ (x^2 + 1) + 4 ]
= [ ( x^2 + 1 )+ 4 ) ] [ 4 ( x^2 + 1 ) - 3 ]
= ( x^2 + 1 + 4 ) ( 4 x^2 + 4 - 3 )
= ( x^2 + 5 ) ( 4 x^2 + 1 )
_______________________________
4 (x^2 + 1 )^2 + 13 ( x^2 + 1 ) - 12
=4( x^2 + 1)^2 + 16 ( x^2 + 1 ) - 3 ( x^2 + 1 ) - 12
= 4 ( x^2 + 1 ) [ (x^2 + 1 )+ 4 ] - 3 [ (x^2 + 1) + 4 ]
= [ ( x^2 + 1 )+ 4 ) ] [ 4 ( x^2 + 1 ) - 3 ]
= ( x^2 + 1 + 4 ) ( 4 x^2 + 4 - 3 )
= ( x^2 + 5 ) ( 4 x^2 + 1 )
_______________________________
ranikv:
thanks for this
WELCOME
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